What is the factored form of the expression?

21x^2 + 20x + 4

21x^2 + 20x + 4 = (3x + 2) (7x + 2).

Step-by-step explanation:

Given the expression is 21x² + 20x + 4

We can solve the equation as follows:-

21x² + 20x + 4 = 0

Then a = 21, b = 20, c = 4.

Using Quadratic formula, x = (-b ± √ (b² - 4ac)) / 2a

x = (-20 ± √ (400 - 4*21*4)) / 2*21

x = (-20 ± √ (400 - 336)) / 42

x = (-20 ± √ (64)) / 42

x = (-20 ± 8) / 42

x = - 28/42 or x = - 12/42

x = - 2/3 or x = - 2/7

(x + 2/3) = 0 or (x + 2/7) = 0

Now the factored form can be written as follows:-

(x + 2/3) (x + 2/7) = 0

(3x+2) (7x+2) = 0

Hence, the factored form is 21x^2 + 20x + 4 = (3x+2) (7x+2).