Ask Question
17 May, 23:00

A group of art students are painting a mural on a walls the rectangular wall has dimensions of (6x+7) by (8x+5) and they are planning the mural to be (x+4) by (2x+5). What is the area of the remaining wall after the mural has been painted

+1
Answers (2)
  1. 17 May, 23:29
    0
    46x^2 + 73x + 15

    Step-by-step explanation:

    Expand both equations

    Wall = (6x + 7) (8x + 5) = 48x^2 + 56x + 30x + 35 = 48x^2 + 86x + 35

    Mural = (x + 4) (2x + 5) = 2x^2 + 5x + 8x + 20 = 2x^2 + 13x + 20

    Minus them.

    Wall - Mural =

    (48x^2 + 86x + 35) - (2x^2 + 13x + 20)

    (48x^2 - 2x^2) + (86x - 13x) + (35 - 20)

    46x^2 + 73x + 15
  2. 18 May, 02:48
    0
    46x^2 + 73x + 15

    Step-by-step explanation:

    Expand both equations

    Wall = (6x + 7) (8x + 5) = 48x^2 + 56x + 30x + 35 = 48x^2 + 86x + 35

    Mural = (x + 4) (2x + 5) = 2x^2 + 5x + 8x + 20 = 2x^2 + 13x + 20

    Minus them.

    Wall - Mural =

    (48x^2 + 86x + 35) - (2x^2 + 13x + 20)

    (48x^2 - 2x^2) + (86x - 13x) + (35 - 20)

    46x^2 + 73x + 15
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A group of art students are painting a mural on a walls the rectangular wall has dimensions of (6x+7) by (8x+5) and they are planning the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers