A particle moves along the x-axis so that at any time t, measured in seconds, its position is given by s (t) = sin (t) - 4cos (2t), measured in feet. What is the acceleration of the particle at time t = π seconds?

Question

Mathematics

Odin Zhang

4 September, 02:25

A particle moves along the x-axis so that at any time t, measured in seconds, its position is given by s (t) = sin (t) - 4cos (2t), measured in feet. What is the acceleration of the particle at time t = π seconds?

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Answers (1)

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Troy Fisher · Answer 1

16 ft/s²

Step-by-step explanation:

s (t) = sin (t) - 4cos (2t)

Differentiation for v

v (t) = cos (t) + 8sin (2t)

Differentiate for a

a (t) = - sin (t) + 16cos (2t)

At t = π

a (π) = - sin (π) + 16cos (2π)

= 0 + 16

= 16