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9 May, 18:28

If f (x) = 2x^2-8, what is f (2y)

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  1. 9 May, 21:40
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    The answer is f (2y) = 8y^2 - 8

    In order to find this, we need to put 2y in where x was in the original equation. From there, we follow the order of operations to simplify.

    f (x) = 2x^2 - 8

    f (2y) = 2 (2y) ^2 - 8

    f (2y) = 2 (4y^2) - 8

    f (2y) = 8y^2 - 8
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