If f (x) = 2x^2-8, what is f (2y)

The answer is f (2y) = 8y^2 - 8

In order to find this, we need to put 2y in where x was in the original equation. From there, we follow the order of operations to simplify.

f (x) = 2x^2 - 8

f (2y) = 2 (2y) ^2 - 8

f (2y) = 2 (4y^2) - 8

f (2y) = 8y^2 - 8