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27 August, 04:44

For what natural values of n is the difference (2-2n) - (5n-27) positive?

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Answers (2)
  1. 27 August, 05:12
    0
    (2 - 2n) - (5n - 27) > 0

    -7n + 27 + 2 > 0

    -7n > - 29

    n < 29/7 < 4.143

    So the natural values of n to make the expression positive are

    1, 2, 3 and 4 (answer)
  2. 27 August, 08:16
    0
    (2-2n) - (5n-27) >0

    distribute

    2-2n - 5n + 27 >0

    combine like terms

    -7n + 29 >0

    subtract 29 from each side

    -7n> - 29

    divide by - 7 (flips the inequality)

    n < - 29/-7

    n <4.14

    natural numbers are 1,2,3,4 ...

    n must be 1,2,3,4

    Answer: 1,2,3,4
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