In the game of "odd man out" each player tosses a fair coin. if all the coins turn up the same except for one, the player tossing the different coin is declared the odd man out and is eliminated from the contest. suppose that three people are playing. what is the probability that someone will be eliminated on the first toss?

Question

Mathematics

Marco

19 May, 05:46

In the game of "odd man out" each player tosses a fair coin. if all the coins turn up the same except for one, the player tossing the different coin is declared the odd man out and is eliminated from the contest. suppose that three people are playing. what is the probability that someone will be eliminated on the first toss?

+3

Answers (1)

Know the Answer?

Ernesto Liu · Answer 1

The options are H, H, T or T, T, H

HHT: 1/2 x 1/2 x 1/2 = 1/8

TTH: 1/2 x 1/2 x 1/2 = 1/8

HHT or TTH: 1/8 + 1/8 = 2/8 = 1/4

Answer: 1 out of 4 = 1/4 = 25%