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28 August, 20:49

The height of a projectile in feet at time t is determined by the equation h=-16t^2+128t+320. At what time will the projectile be 560 feet high

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Answers (2)
  1. 28 August, 21:01
    0
    At 3 seconds and again at 5 seconds

    Step-by-step explanation:

    h = - 16t² + 128t + 320

    560 = - 16t² + 128t + 320

    16t² - 128t + 240 = 0

    t² - 8t + 15 = 0

    t² - 5t - 3t + 15 = 0

    t (t - 5) - 3 (t - 5) = 0

    (t - 5) (t - 3) = 0

    t = 3, t = 5
  2. 28 August, 21:58
    0
    3 seconds and 5 seconds

    Step-by-step explanation:

    Let the function equal 560 ft

    560=-16t^2+128t+320

    Subtract 560 from each side

    560-560=-16t^2+128t+320-560

    0 = -16t^2+128t-240

    Divide each side by - 16

    0/-16 = (-16t^2+128t-240) / -16

    0 = t^2 - 8t-15

    Factor

    0 = (t-5) (t-3)

    Using the zero product property

    t-5 = 0 t-3=0

    t=5 t=3
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