The length of a rectangle is 11 feet more than the width. If the perimeter is 62 feet then what is the length of a rectangle in feet? I dont know how I got 110.

The length is 21 ft

Step-by-step explanation:

w = width

l = w+11

The formula for perimeter is

P = 2 (l+w)

62 = 2 (w+11+w)

Combine like terms

62 = 2 (2w+11)

Divide each side by 2

62/2 = 2/2 (2w+11)

31 = 2w+11

Subtract 11 from each side

31-11 = 2w+11-11

20 = 2w

Divide each side by 2

20/2 = 2w/2

10 = w

Now find the length

l = w+11

l = 10+11

l = 21

The length is 21 ft

21

Step-by-step explanation:

The length is equal to the width plus 11. So we can write an equation like this: 62 = 4w + 22. We subtract 22 from both sides, and get 40 = 4w. Divide by 4 on both sides, and we know that 10 equals width. The length is 11 more than the width, so 10+11=21.