How do you solve algebra special systems

solve each system of linear equations.

y equals negative x minus 3

x plus y equals 4

Y=-X-3

X+Y=4

You'll want to get X or Y by itself, which in this question it already is.

After that, use substitution (Plug - X-3 in place of Y in X+Y=4)

Equation should look like X + (-X-3) = 4

Solve that equation

X + (-X-3) = 4

X + (-X) cancels eachother out, leaving you with (-3) = 4

Add 3 to both sides of (-3) = 4, leaving you with 0=7

0 Can't equal 7, so this equation has no solutions