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18 December, 23:42

Find a in a geometric series for which Sn = 728, r = 3, and n = 6.

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  1. 19 December, 01:33
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    a = 2

    Step-by-step explanation:

    In geometric series, Sum of the series formula:

    Sn = a[ (rⁿ - 1) / (r - 1) ]

    We are given that Sn = 728 and

    r = 3 and n = 6

    Thus, plugging in the relevant values;

    728 = a[ (3^ (6) - 1) / (3 - 1) ]

    728 = 364a

    a = 728/364

    a = 2
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