Solve and find the integer of 4x^2-19x-5

(x-5) (4x+1)

4x^2 times - 5 is - 20 the factors of - 20 are - 1x20, 1x-20 ... but to make the - 19x you would add together the 1 and - 20 because 1-20 is - 19.

This then splits off to factorise 4x^2-20x, making this side 4x (1x-5) carry the brackets over to make it 1 (1x-5) joining the brackets together to make (4x+1) (x-5)