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6 February, 15:12

A chemist needs 30mL of a 12% acid solution for an experiment. The lab has available a 10% solution and a 25% solution. How many milliliters of the 10% solution and how many milliliters of the 25% solution should the chemist mix to make the 12% solution?

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  1. 6 February, 15:46
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    parts of 10% soln, x

    parts of 25% soln, y

    total soln, x+y = 30

    {x (0.1) + y (0.25) } / (x + y) = 0.12 ... eqn 1

    x + y = 30 ... eqn 2

    from eqn 2 ... = " x = 30-y

    subst for x in eqn 1 ...

    =" { (30-y) (0.1) + y (0.25) } / 30-y+y = 0.12

    =" (3-.1y+.25y) / 30 = 0.12

    =" 3+.15y = 3.6

    =".15y =.6

    =" y = 4

    using x = 30 - y = 26

    ans

    26ml of 10% soln

    4ml of 25% soln
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