Find the vertex V and the x-intercepts x^1 and x^2 of the quadratic function f (x) = 2x^2 - 8x.

A.

V (2, - 8); x^1 = 0, x^2 = 4

B.

V (2, - 4); x^1 = 0, x^2 = 4

C.

V (0, 0); x^1 = - 2, x^2 = 4

D.

V (0, 0); x^1 = 2, x^2 = - 8

Question

Chen

17 August, 01:01

+3

Answers (1)

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Blaine White · Answer 1

Blaine White 17 August, 01:36

0

I believe the answer is A

Find the vertex V and the x-intercepts x^1 and x^2 of the quadratic function f (x) = 2x^2 - 8x.A.V (2, - 8); x^1 = 0, x^2 = 4B.V (2, - 4); x^1 = 0, x^2 = 4C.V (0, 0); x^1 = - 2, x^2 = 4D.V (0, 0); x^1 = 2, x^2 = - 8