Ask Question
26 February, 03:51

At least how many grams of copper must be alloyed with 387 g of pure silver to produce an alloy that is no more than 90% pure silver

+3
Answers (1)
  1. 26 February, 04:23
    0
    Let c = grams of copper to be added

    (grams of silver) / (grams of copper and silver) < =.90

    387+%2F+%28c+%2B+387%29+%3C=+.9

    387+%3C=+.9%28c+%2B+387%29

    387+%3C=+.9c+%2B+348.3

    .9c+%3E=+387+-+348.3

    .9c+%3E=+38.7

    c+%3E=+43g

    At least 43 grams of copper must be added

    check:

    387+%2F+%28c+%2B+387%29+%3C=+.9

    387+%2F+%2843+%2B+387%29+%3C=+.9

    387+%2F+430+%3C=+.9

    .9+%3C=+.9
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “At least how many grams of copper must be alloyed with 387 g of pure silver to produce an alloy that is no more than 90% pure silver ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers