What are the vertical asymptote (s) and hole (s) for the graph of y = x-1 over X squared + 6x + 8

You have vertical asymptotes on x=-4,-2

Step-by-step explanation:

This question is very simple. Since you have a denominator all you need to do is factor the bottom and find the zeros. When you factor the bottom of the equation you should get (x+4) (x+2). Now you have to set the bottom equal to zero to find the zeros. This means (x+4) = 0 and (x+2) = 0 So you get two answers x=-4 and x=-2 Therefore your two vertical asymptotes are on x-4,-2