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19 June, 02:38

What is the radius of a sphere with a volume of 5271 m^3, to the nearest tenth of a meter?

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Answers (2)
  1. 19 June, 06:23
    0
    R = 10.8m Using the formula V = 4/3 π r3

    Solving for R = r = (3V

    4π) ⅓ = (3·5271

    4·π) ⅓≈10.79613m
  2. 19 June, 06:37
    0
    10.8 m

    Step-by-step explanation:

    The volume of a sphere is given by

    V = 4/3 pi r^3

    We know the volume is 5271

    5271 = 4/3 * 3.14 * r^3

    5271 = 4.18666666 * r^3

    Divide each side by 4.186666666

    5271/4.18666666 = r^3

    1258.996815 = r^3

    Take the cube root of each side

    (1258.996815) ^1/3 = (r^3) ^1/3

    10.7979 = r

    To the nearest tenth of a meter

    10.8 = r
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