What are the solutions to the equation and check for extraneous solutions:

16 = (x-2) ^2/3

Question

Mathematics

Kenyon Camacho

8 January, 15:32

What are the solutions to the equation and check for extraneous solutions:

16 = (x-2) ^2/3

+1

Answers (1)

Know the Answer?

Fernando Fernandez · Answer 1

we have x = - 62 or x = 66

Step-by-step explanation:

16 = (x-2) ^2/3

I would take square root first

4 = (x - 2) ^ (1/3)

or - 4 = (x - 2) ^ (1/3)

...

4^3 = x - 2

64 = x - 2

x = 66

or - 4 ^3 = x - 2

-64 = x - 2

x = - 62

we have x = - 62 or x = 66

What are the solutions to the equation and check for extraneous solutions:16 = (x-2) ^2/3

What are the solutions to the equation and check for extraneous solutions:

16 = (x-2) ^2/3