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9 September, 13:53

The roots a and b of the quadratic equation x2+kx+12=0 are such that a-b=1. determine k.

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  1. 9 September, 16:20
    0
    Simplifying

    x2+kx + - 12=0

    Recorder the terms: - 12+kx+x2 = 0

    solving: - 12 + kx + x2=0

    now solving for variable 'K'

    move all the terms containing K to the left, all other terms to the right.

    Add '12' to each side of the equation.

    -12+12+kx + x2 = 0+12

    combine like terms: - 12+12=0

    0+kx + x2=0+12

    combine like terms: 0+12=12

    kx+x2+-1x2 = 12 + - 1x2

    combine like terms: x2 + - 1x2=0

    kx+0 = 12+-1x2

    kx = 12+-1x2

    divide each side by 'x'.

    k=12x-1 + x

    simplifying: K=12x - 1 + - 1x

    Anw: K=12x - 1 + - 1x
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