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2 March, 02:39

Write the following expression as a single

logarithm with coefficient 1.

log3 (6c) + log3 1/12

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Answers (2)
  1. 2 March, 04:36
    0
    Answer: the answer is log3 (c/2)
  2. 2 March, 06:04
    0
    log3 {c/2}

    Step-by-step explanation:

    Addiing two logs together is equivalent to multiplying their arguments.

    Thus,

    log3 (6c) + log3 1/12 = log3 6*c*[1/12], or log3 (log3 [6c][1/12]).

    This simplifies to log3 {c/2} because 6c (1/12) = c/2
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