What is the value of 6i/1+i? 2 - 6i 2 + 6i 3 - 3i 3 + 3i

6i / (1+i)

multiply by the complex conjugate (1-i) / (1-i)

6i / (1+i) * (1-i) / (1-i)

6i * (1-i) = 6i - 6i^2 = 6i - 6 (-1) = 6i + 6

(1+i) * (1-i) = 1-i + i - i^2 = 1 - i+i - (-1) = 1+1=2

(6+6i) / 2

3+3i

Answer: 3+3i

D. 3+3i