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MathematicsMathematics
17 March, 14:40

At Jaxlyn's Garage, 200 cars were inspected and worked on. There were 92 cars that

needed new brakes, 136 cars that needed a new alternator, and 24 cars that needed

neither repair.

Part A: Determine the probability of a car needing both repairs.

Part B: Determine the probability of a car needing an alternator, but not new brakes.

+4
Answers (1)
  1. 17 March, 16:03
    0
    A) 0.26

    B) 0.42

    Step-by-step explanation:

    No. of cars which needed both:

    92 + 136 - (200 - 24)

    52

    P (both) = 52/200 = 0.26

    No. of cars that need an alternator, but not new brakes:

    136 - 52

    84

    P = 84/200 = 0.42
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Home » Mathematics » At Jaxlyn's Garage, 200 cars were inspected and worked on. There were 92 cars that needed new brakes, 136 cars that needed a new alternator, and 24 cars that needed neither repair. Part A: Determine the probability of a car needing both repairs.
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