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6 April, 15:33

Rover's cylinder dog bowl has a diameter of 6 inches and a height of 2 inches. Approximately how much water does it hold? Use 3.14 for pi and round your answer to the nearest cubic inch.

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Answers (2)
  1. 6 April, 18:29
    0
    volume of the cylindrical dog bowl ≈ 57 inches³ (nearest cubic inches)

    Step-by-step explanation:

    The amount of water the cylindrical dog bowl can hold is the volume of the cylindrical dog bowl.

    volume of a cylinder = πr²h

    where

    r = radius

    h = height

    r = 6/2 = 3 inches

    h = 2 inches

    volume of a cylinder = πr²h

    volume of a cylinder = π * 3² * 2

    volume of a cylinder = π * 9 * 2

    volume of a cylinder = π * 18

    volume of a cylinder = 3.14 * 18

    volume of the cylindrical dog bowl = 56.52 inches³

    volume of the cylindrical dog bowl ≈ 57 inches³
  2. 6 April, 18:33
    0
    56.5 cubic inch

    Step-by-step explanation:

    The Volume of a cylinder can be written as;

    V = πr^2 h ... 1

    Where;

    Radius = r

    Height = h

    Given;

    Radius r = diameter/2 = 6/2 = 3 inches

    height h = 2 inch

    π = 3.14

    Substituting the values into the equation 1;

    V = 3.14 * 3^2 * 2

    V = 56.5 cubic inch

    The amount of water it can hold is equal to the volume of the cylinder which is equal to 56.5 cubic inch
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