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21 September, 03:37

Which values of x and y would make the following expression represent a real number? (6 + 3i) (x + yi) Options: x = 6, y = 0 x = - 3, y = 0 x = 6, y = - 3 x = 0, y = - 3

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  1. 21 September, 04:06
    0
    (x + yi) must be the conjugate of the complex number (6 + 3i).

    ⇒ x + yi = 6 - 3i

    ⇒ x = 6 and y = - 3 Verification: (6 + 3i) (6 - 3i) = 6² - (3i) ² = 36 + 9 = 45 ∈ RAttention! i² = - 1
  2. 21 September, 04:17
    0
    The answer is option 3. or C.

    x = 6, y = - 3
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