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Today, 01:53

Prove 1 + cos (2 θ) 2 / cos (θ) = cos (θ) is an identity

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  1. Today, 02:09
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    prove [1 + cos (2 θ) ] / 2cos (θ) = cos (θ) is an identity

    [ 1 + cos (2 θ) ] / 2cos (θ)

    cos (2θ) = 2 (cos θ) ^2 - 1

    so plug 2 (cos θ) ^2 - 1 in for cos (2 theta)

    [ 1 + 2 (cos θ) ^2 - 1 ] / 2cos (θ)

    = [ 2 (cos θ) ^2 ] / 2cos (θ)

    = [ (cos θ) ^2 ] / cos (θ)

    = (cos θ)

    so (cos θ) = (cos θ) is true. Proven.

    Step-by-step explanation:

    prove [1 + cos (2 θ) ] / 2cos (θ) = cos (θ) is an identity

    ...

    we need to show that the expression on the left side will eventually transform into cos (Θ)

    Start with [1 + cos (2 θ) ] / 2 cos (θ)

    prove [1 + cos (2 θ) ] / 2cos (θ) = cos (θ) is an identity

    [ 1 + cos (2 θ) ] / 2cos (θ)

    cos (2θ) = 2 (cos θ) ^2 - 1

    so plug 2 (cos θ) ^2 - 1 in for cos (2 theta)

    [ 1 + 2 (cos θ) ^2 - 1 ] / 2cos (θ)

    = [ 2 (cos θ) ^2 ] / 2cos (θ)

    = [ (cos θ) ^2 ] / cos (θ)

    = (cos θ)

    so (cos θ) = (cos θ) is true. Proven.
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