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4 November, 09:21

A rectangle has a height of 4w^3 and a width of 5w^2-3w-4 what is the area

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  1. 4 November, 12:44
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    A = 5w^5 - 3w^4 - 4w^3

    Step-by-step explanation:

    The area of a rectangle

    A = (l * b)

    A - area of a rectangle

    l - length/height of a rectangle

    b - breadth / width of a rectangle

    Given

    h = 4w^3

    w = 5w^2 - 3w - 4

    A = h * w

    A = 4w^3 * 5w^2 - 3w - 4

    = 4w^3 (5w^2 - 3w - 4)

    Hint: 4w^3 * 5w^2 = 20w^5

    w^3 * w^2 = w^3+2

    = w^5

    4w^3 * - 3w = - 12w^4

    w^3 * w = w^3 + 1

    = w^4

    4w^3 * - 4 = - 16w^3

    Collect the terms

    = 20w^5 - 12w^4 - 16w^3

    Simply further by dividing through by 2

    = 10w^5 - 6w^4 - 8w^3

    Simply by dividing through by 2

    = 5w^5 - 3w^4 - 4w^3
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