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16 May, 13:26

How do i solve 2k^2-5k-18=0

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  1. 16 May, 15:55
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    factor left the side of the equation

    (2k_9) (k+2) = 0

    set factors equal to 0

    2k_9=0 or k+2=0

    the answer is K = 9/2 or K = -2
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