Solve the following quadratic equations by completing the square.

y^2-14y+48=0

y = 6 or 8

Step-by-step explanation:

1. Subtract the constant:

y^2 - 14y = - 48

2. Add the square of half the y-coefficient:

y^2 - 14y + 49 = - 48 + 49

Write as a square, if you like:

(y - 7) ^2 = 1

3. Take the square root:

y - 7 = ±√1 = ±1

4. Add the opposite of the constant on the left:

y = 7 ±1 = 6 or 8

The solution is y = 6 or y = 8.