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27 August, 00:48

Y^2 - 14y + 48 = 0

Solve the following quadratic equations by completing the square.

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Answers (1)
  1. 27 August, 04:17
    0
    Step by step:

    y^2 - 14y+48=0

    y^2-14y=-48

    y^2-14y+49=-48+49

    (y-7) ^2=1

    Answer: y=7+-1
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