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10 September, 14:44

Two cyclist leaves town 200 mi apart at the same time and travel toward each other. One travels at 10mi/h slower than the other. The they meet in 5 hours, what is the rate of each cyclist

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  1. 10 September, 14:50
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    Let x be the rate of speed of slower cyclist

    and x+10 = rate of speed of faster cyclist

    Distance = Speed * Time

    5x + 5 (x+10) = 200

    5x + 5x + 50 = 200

    10x = 200-50

    10x = 150

    x = 15

    Rate of speed of slower cyclist: 15 mph

    Rate of speed of faster cyclist = 15+10 = > 25 mph
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