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23 March, 18:10

Identify the horizontal asymptote of f (x) = x2+5x-3/4x-1

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  1. 23 March, 18:45
    since the numerator is x² + 5x - 3, and therefore has a degree of 2, whilst the denominator, 4x¹ - 1, has a degree of 1, therefore, there's no horizontal asymptote.

    recall, we only get a horizontal asymptote if the denominator's expression degree is equals or greater than that of the numerator's.
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