Suppose that in a particular country, the probability that a randomly chosen person is a left-handed baseball player is 0.015 0.015 and the probability that a randomly chosen baseball player is left-handed is 0.240. 0.240. Based on these probabilities, determine the probability, p, p, that a randomly chosen person from this country plays baseball. Give your answer as a decimal precise to at least three decimal places.

Question

Emmett Mason

6 May, 07:37

+1

Answers (1)

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Quinten Cruz · Answer 1

0.0625

Step-by-step explanation:

P (left/baseball) =

P (baseball ^ left) / P (baseball)

0.24 = 0.015/P (baseball)

P (baseball) = 1/16 or 0.0625