If the radius of the circle is 12 inches, the area of the sector contained by the minor arc and two radii is what?

113.14 Inches²

Step-by-step explanation:

The area of a sector A contain by the minor arc of a circle is given as

A = Ф°/360 * πr²

Where Ф is the angle formed in the arc, π is a constant given as 22/7 and r is the radius of the circle.

Given that the minor arc is contained by two radii, the angel between them is 90° hence, the area of the arc

= 90/360 * 22/7 * 12²

= 113.14 Inches²