A store sells shirts at three prices only: $25, $30, and $35. How many different combinations are possible for the store to sell 20 shirts for a total of $600?

Question

Mathematics

Case Harper

20 November, 08:43

A store sells shirts at three prices only: $25, $30, and $35. How many different combinations are possible for the store to sell 20 shirts for a total of $600?

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Answers (1)

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Lilibeth · Answer 1

11

Step-by-step explanation:

The average price of the 20 shirts is 600/20 = $30 each. So, we know that we can sell 20 shirts for $30 each to reach the goal.

For each $25 shirt we sell, we must also sell a $35 shirt to make the average price of the sale be $30 per shirt. That is any or all of the 10 pairs of $30 shirts can be replaced by a ($25, $35) pair. So, there are 10 additional ways to reach the goal.

The total number of possible combinations of shirt sales is 1 + 10 = 11.