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30 October, 01:16

Given sinθ=4/7 and θ lies in Quadrant II.

What is the exact value of cosθ in simplified form?

-4√33/33

-√33/4

√33/7

-√33/7

+3
Answers (1)
  1. 30 October, 02:46
    0
    Answer:-√33/7

    Step-by-step explanation:

    Second quadrant implies cos negative, as cos is projection from

    unit circle to x axis.

    sin^2+cos^2=1

    cos = sqrt (1-sin^2)

    sin^2 = 16/49

    1-sin^2 = 33/49

    sin = - sqrt (33) / 7
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