If the length of the square is increased by 2 and the width is decreased by 2, by how many units is the area of

the square bigger than the area of the new rectangle?

4 units

Step-by-step explanation:

Let x represent the length of the square

Area of the square = x^2

So, the dimension of the rectangle formed is:

length = x + 2

width = x - 2

Area of the rectangle = (x + 2) * (x - 2)

solve the parenthesis

x^2 - 2x + 2x - 4

Area of the rectangle = x^2 - 4

subtract this area from that of the square

x^2 - (x^2 - 4)

=x^2 - x^2 + 4

= 4 units