About 5.67811 X10^5 liters of water flow over Niagara Falls per second there are 3.15576 x10^7 seconds in one year the number of liters of water that flows over Niagara Falls each year are about 5.67811 x 10^5 x3.15476x10^7

A. 1e12

B. 179187524.1

C. 1.791875241e13

D. 1.92559524e-44

C. 1.791875241e13

Step-by-step explanation:

We have that,

Amount of water flows over Niagara Falls per second = 5.67811*10⁵

Also, the number of seconds in a year = 3.15576*10⁷

Thus,

Liters of water that flows in a year = Amount of water that flows * Number of seconds

i. e. Liters of water = 5.67811 * 10⁵ * 3.15576 * 10⁷

i. e. Liters of water = 17.91875241 * 10¹²

i. e. Liters of water = 1.791875241 * 10¹³

Hence, the liters of water that flows through Niagara Falls each year is 1.791875241 * 10¹³ i. e. 1.791875241e13

1.791875241e13

Step-by-step explanation:

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