Ask Question
11 March, 00:07

if 10 800 cm2 of material is available to make a box with a square base and an open top find the largest possible volume of the box.

+2
Answers (1)
  1. 11 March, 03:37
    0
    What are you given variables?

    Surface area of box: 10800cm²

    Volume of box: s²h

    Where:

    SA=surface area

    s = side of square base

    h = height of box

    Make the height of the box in terms of s

    You can write the formula for the surface area of the box in terms of s and h like so:

    S. A. = s² + 4sh

    Where: S. A. = surface area or 1200 cm², s² = the square base, and 4sh = the four 'walls' of the box.

    10800 = s² + 4sh

    10800 - s² = 4sh

    (10800 - s²) / (4s) = h

    Substitute h (in terms of s) into the formula for volume.

    v (s) = s² ((10800 - s²) / (4s)) / / Simplify.

    v (s) = s (10800 - s²) / 4 / / Expand.

    v (s) = 2700s - (1/4) s^3 / / To find the largest possible volume of the box, you find the maximum value of this function.

    Take the derivative of the volume function using the Power Theorem.

    v' (s) = 2700 - (3/4) s² / / Zeroes of the d/dx v function will give you the x values that correspond to local extrema in the v function.

    0 = 2700 - (3/4) s² / / Solve for zeroes.

    -2700 = (-3/4) s²

    3600 = s²

    Your two zero values for s are - 60 and 60.

    Take the second derivative to see if the s values will give you a local maximum or minimum.

    v" (s) = - (3/2) s

    v" (-60) = - (3/2) (-60)

    v" (-60) = 90 / / This indicates a local minimum for v at s, not what we are looking for.

    v" (60) = - (3/2) (60)

    v" (60) = - 90 / / This indicates a local maximum for v at s, which is what we are looking for, the maximum volume of the box. This makes sense because if you remember what we assigned the variable s to, a side length, side lengths cannot be negative.

    Once we have found the value for s, we can substitute it into the function we created for the volume of the box.

    v (s) = 2700s - (1/4) s^3

    v (s) = 2700 (60) - (1/4) (60) ^3

    v (s) = 162000 - (1/4) (216000)

    v = 162000 - 54000

    The largest possible volume of the box is 108000 cubic centimeters.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “if 10 800 cm2 of material is available to make a box with a square base and an open top find the largest possible volume of the box. ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers