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23 September, 22:55

For the quadratic equation y=-2 (x+2) ^2+3 what is the vertex

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  1. 24 September, 02:52
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    The vertex (-2,3) is the answer.

    Step-by-step explanation:

    * For y = ax^2 + bx + c, we have the vertex (-b/2a, - delta/4a)

    * For y = a (x+m) ^2 + n, the vertex is (-m, n)

    * For: y = - 2 (x+2) ^2 + 3, we have the vertex (-2, 3).

    The vertex (-2,3) is the answer.

    Hope you understand.
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