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2 October, 09:39

If a ball is thrown upward at 29.4 meters per second from the top of a building that is 80 meters high, the height of the ball can be modeled by S=4.9t^2 + 29.4t + 80 meters, where t is the number of seconds after the ball is thrown. What is the ball's maximum height (in meters) ?

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  1. 2 October, 12:06
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    124.1m

    Step-by-step explanation:

    29.4 per sec > Building 80m

    Height = S = 4.9t^2 + 29.4t + 80

    Solve for t:

    t = 1.24 (approximately)

    If t needed coordinates / solve using the quadratic formula:

    t = (1.24, - 7.24)

    The ball's maximum height is 124.1 meters.
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