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24 August, 02:22

When the polynomial 4x^4 - 13x^2 - 2x is divided by the polynomial x - 2, x-2, what is the remainder?

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  1. 24 August, 02:53
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    Let p (x) = 4x^4-13x^2-2x

    The zero of x-2 is 2

    putting x = 2 in p (x), we get,

    p (2) = 4*2^4-13*2^2-2*2

    = 64 - 52 - 4

    = 64 - 56

    = 8

    Therefore, remainder = 8
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