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31 January, 20:09

SecA=√6.00, find tanA

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  1. 31 January, 22:34
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    tan (A) = √5

    Step-by-step explanation:

    The relation between secant and tangent is ...

    tan² (A) + 1 = sec² (A)

    Then ...

    tan (A) = √ (sec² (A) - 1) = √ (6 - 1)

    tan (A) = √5
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