How many real solutions does the equation 8x^2 - 10x + 15 = 0 have?

It has no real solutions.

Step-by-step explanation

Once you calculate the discriminant, D = (-10) ^2 - 4 (8) (15), you simplify the expression to get D = - 380, which has no real solutions.

No solutions

Step-by-step explanation:

Quadratic equations are in the form of ax^2+bx+c, so a = 8, b = - 10, and c = 15.

Use b^2 - 4ac to find the discriminant.

-10^2 - 4 (8) (15) = - 580

If a discriminant is < 0 then there are no real solutions to a quadratic equation. - 580 < 0

Therefore, there are no real solutions