Sighting the top of a building, a surveyor measured the angle of elevation to be 60 degrees. The measurement is taken 200 feet from the building. Find the building's height. Express your answer in terms of feet and then round to two decimls.

This is a 30-60-90 triangle

opposite side of rigt angle=2x

opposite side of 60 degrees is x√3

opposite sides of 30 degree is x

the right angle is at the base of the building so therefor

200=x

2x=distance from surveor to top of building and x√3=height of building

x=200

200√3≈346.41

the answer is 346.41 feet

Tan (60) = opposite/200

height = 200tan (60) = 200sqrt (3) or about

346.41 ft