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10 February, 09:10

Find the standard form of the following equation y = (x-3) ^2-5

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  1. 10 February, 10:06
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    y = x^2 - 6x + 4

    Step-by-step explanation:

    The equation of a parabola in "standard form" is y = ax^ 2 + bx + c.

    Expanding y = (x-3) ^2 - 5, we get y = x^2 - 6x + 9 - 5, or y = 1x^2 - 6x + 4. y = x^2 - 6x + 4 would be an adequate answer also.
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