What are the x-intercepts of the quadratic function? y = x2 - 3x + 2

A) 2 and 1

B) - 2 and 1

C) 2 and - 1

D) 1

y = x² - 3x + 2

The x-intercepts can be take by matching the equation to 0, so,

x² - 3x + 2 = 0

Δ = b² - 4. a. c

Δ = - 3² - 4. 1. 2

Δ = 9 - 4. 1. 2

Δ = 1

There 2 real roots.

x = (-b + - √Δ) / 2a

x' = (--3 + √1) / 2.1

x'' = (--3 - √1) / 2.1

x' = 4 / 2

x'' = 2 / 2

x' = 2

x'' = 1

Alternative A.