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19 October, 15:08

Im stuck on a algebra 2 question

f (x) = - 2x + 8 and g (x) = 3x^2 - 1

find f (f (-2))

+4
Answers (2)
  1. 19 October, 15:48
    0
    f (f ( - 2)) = - 16

    Step-by-step explanation:

    To evaluate f (f ( - 2)), evaluate f ( - 2) then evaluate f (x) for this value

    f ( - 2) = ( - 2 * - 2) + 8 = 4 + 8 = 12, hence

    f (12) = ( - 2 * 12) + 8 = - 24 + 8 = - 16
  2. 19 October, 18:37
    0
    f (f (-2) = - 16

    Step-by-step explanation:

    The first step is to evaluate the function f at - 2

    f (-2) = - 2 (-2) + 8

    f (-2) = 4+8

    =12

    Then we evaluate the function f at x=12

    f (12) = - 2 (12) + 8

    = - 24 + 8

    = - 16

    f (f (-2) = - 16
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