Y varies directly with the square of X. If y = 5 when x=3, what is the value of y when x=9?

Question

Mathematics

Arturo Moreno

10 March, 19:34

Y varies directly with the square of X. If y = 5 when x=3, what is the value of y when x=9?

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Answers (1)

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Everett Wolf · Answer 1

Answer:45

Step-by-step explanation:

y varies directly as x^2

y=k x x^2

When y=5 x=3

5=k x 3^2

5=k x 9

K=5/9

Relationship is y=5x^2/9

y = (5x9^2) ➗ 9

y = (5x81) ➗ 9

y=405 ➗ 9

y=45