Ask Question
13 January, 07:39

A jar contains 4 red marbles, 4 green marbles, and 5 blue marbles.

If we choose a marble, then another marble without putting the first one back in the jar, what is the probability that the first marble will be blue and the second will be green?

+1
Answers (1)
  1. 13 January, 08:28
    0
    20/156 or 5/39

    Step-by-step explanation:

    the first part of the equation will be:

    5/13 (5 is how many blue and 13 is altogether)

    the next part of this equation is the green marble. Because we didn't put the blue marble back, the next part of the equation will be:

    4/12 (4 is how many green and 12 is altogether now that one blue was taken out)

    and from there, you multiply 5/13 with 4/12, with will give you 20/156, or 5/39 if you simplify.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A jar contains 4 red marbles, 4 green marbles, and 5 blue marbles. If we choose a marble, then another marble without putting the first one ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers