Carlos and his friends Jada are going on a long hike. The plan to bring 5.2 liters of water for hike. They bring 8 bottles. Carlos only has a large bottles that can hold 0.88 liter of water. Jada only has small bottles that can hold 0.42 liter of water. How many large bottles does Carlos need to bring?

Well to solve this the way that I used was just to guess and check until everything works out. The answer is 4 large bottles and 4 small bottles, because 4+4=8 and 8=8 and then. 88*4=3.62 and. 42*4=1.68 and then 3.62+1.68=5.2=) Enjoy!=)

So using legit math and algebra so

5.2 L

8 bottles so

c=number of bottles brought by carlos

j=number of bottles bought by jada

so j+c=8 and

carlos=.88 lieters and

j=0.42 lieters

so ammount is

0.42j+0.88c=5.2

with the equations

0.42j+0.88c=5.2 and

j+c=8

solve for j and c

j+c=8

subtract c from both sides

j=8-c

subsitute 8-c for j in first equation

0.42 (8-c) + 0.88c=5.2

distribute

3.36-0.42c+0.88c=5.2

add like terms

3.36+0.46c=5.2

subtract 3.36 from both sides

1.84=0.46c

divide both sides by 0.46

4=c

subsitute

c=4

subsiute 4 for c in ffirst equation

c=4

c+j=8

4+j=8

j=4

jada=4 bottles

carlos=4 botles

used legit math