Write - 72=2y^2-16y-20x in standard form

Question

Mathematics

Declan Bryan

5 November, 08:34

Write - 72=2y^2-16y-20x in standard form

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Answers (2)

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Bruce Mcdaniel · Answer 1

-72=-12y-20x

Step-by-step explanation:

-72=2y^2-16y-20x

square the 2 keeping the variable

-72=4y-16y-20x

Then combine like terms in this case the numbers followed by y's

-72=-12y-20x

This is the standard form as there is nothing else you can combine to break this down any further

Adrianna Valenzuela · Answer 2

y = √ 10 (x - 2)

y = - √ 10 (x - 2) + 4 + 4